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Q. GaAs (with a band gap= 1.5 eV) as an LED can emit

KEAMKEAM 2010Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

The band gap= l.5 e V
$ \, \, \, \, \, \, \, \, =1.5 \times 1.6 \times 10^{-19} J$
$ \, \, \, \, \, \, \, =2.40 \times 1^{-19} J$
Wavelength of radiation emitted $(\lambda) =\frac{hc}{E}$
$\, \, \, \, \, \, \, \, \, \, \, =\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{ 2.4 \times 10^{-19}}$
$ \, \, \, \, \, \, \, \, \, =8.25 \times 10^{-7} m$
$ \, \, \, \, \, \, \, \, \, \, =8250 \mathring{A}$
This wavelength belongs to infrared rays.