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Q. From the Zener diode circuit shown in figure, the current through the Zener diode is
image

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Here, $R_L = 5 \times 10^3 \,\Omega$,
$ V_i = 220 \,V$,
Zener voltage, $V_Z = 50\, V$
image
Load current, $I_L = \frac{V_Z}{R_L}$
$ = \frac{50}{20\times 10^3}$
$ = 2.5 \times 10^{-3} \,A$
Current through $R, I = \frac{220 -50}{5\times 10^3}$
$ = 34\times 10^{-3} A$
Zener current,
$I_Z = I - I_L $
$ = 34\times 10^{-3} - 2.5 \times 10^{-3}$
$ = 31.5 \times 10^{-3} A$
$= 31.5\,mA$