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Q. From the base of a pole of height $20$ meter, the angle of elevation of the top of a tower is $60^{\circ}$. The pole subtends an angle $30^{\circ}$ at the top of the tower. Then the height of the tower is:

JEE MainJEE Main 2022Introduction to Three Dimensional Geometry

Solution:

$PT =\frac{ h }{\sqrt{3}}= AB$
$\frac{ AB }{ h -20}=\sqrt{3}$
$h =3( h -20)$
$h =30$
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