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  4. From the above figure, the activation energy for the reverse reaction would be

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Q. From the above figure, the activation energy for the reverse reaction would beChemistry Question Image

Chemical Kinetics

Solution:

Given $\Delta H=-120 \, KJ \, mol^{-1}; E_{a}=1640 KJ \, mol^{-1}$
For reverse reaction, $\Delta H=+120 \, KJ \, mol^{-1}$
$\therefore \,$ Activation energy for the reverse reaction
$=1640+120=+1760 \, KJ \, mol^{-1}$