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Mathematics
From Point p(2,3) two tangents PA and PB are drawn to the hyperbola x2-y2-4 x+4 y+16=0. The equation of line A B is
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Q. From Point $p(2,3)$ two tangents PA and PB are drawn to the hyperbola $x^2-y^2-4 x+4 y+16=0$. The equation of line $A B$ is
Conic Sections
A
$y=3$
B
$ y=2$
C
$x=1$
D
$x=3$
Solution:
$2 x-3 y-2(x+2)+2(y+3)=0$
$-y+2=0 \Rightarrow y=2$