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  4. From a point charge, there is a fixed point A. At A, there is an electric field of 500 V/m and potential difference of 3000 V. Distance between point charge and A will be

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Q. From a point charge, there is a fixed point A. At A, there is an electric field of 500 V/m and potential difference of 3000 V. Distance between point charge and A will be

Electric Charges and Fields

Solution:

E = 500 V/m V = 3000 V.
We know that electric field (E) = 500 = $\frac{V}{d}$
or $d = \frac{3000}{500} = 6m $