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Q. From a high tower at time $t=0$, one stone is dropped from rest and simultaneously another stone is projected vertically up with an initial velocity. The graph of the distance 's' between the two stones, before either hits the ground, plotted against time ' $t$ ' will be as

Motion in a Straight Line

Solution:

$s_{12}=u_{12} t+\frac{1}{2} a_{12} t^{2}$
Now, $u_{12}=u_{1}-u_{2}=(+u)-(-u)=2 u$
$a_{12}=a_{1}-a_{2}=g-g=0 \Rightarrow S_{12}=(2 u) t$
It must be a line of constant slope passing through the origin.