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Q. From a balloon rising vertically upward at $6\, m / s$ a stone is thrown up at $16\, m / s$ relative to the balloon. Its velocity with respect to the ground after $2$ second is:

Motion in a Straight Line

Solution:

Initial velocity of the balloon w.r.t the ground
$u =6+16=22 m / s$
because thrown velocity of stone and balloon is opposite
in direction w.r.t the ground
Velocity after $2$ second $\Rightarrow v=u- gt$
$v=22-10 \times 2 $
$v=22-20=2 m / s$