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Q. From a $200\, m$ high tower, one ball is thrown upwards with speed of $10\, ms ^{-1}$ and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest to

BITSATBITSAT 2020

Solution:

The ball thrown upward will lose velocity in Is. It return back to thrown point in another $1 \,s$ with the same velocity as second. Thus the difference will be $2\, s$.