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Q. Frequency of revolution of an electron revolving in nth orbit of H-atom is proportional to

KCETKCET 2019Atoms

Solution:

Time period of revolution, $T=\frac{2 \pi r}{v}$
Frequency of revolution , $f=\frac{v}{2 \pi r}$
$v \propto\frac{1}{n}
r \propto n^{2}$ and hence $f \propto\frac{1}{n^{3}}$