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Q. Free energy, $G=H-T S$, is a state function that indicates whether a reaction is spontaneous or nonspontaneous. If you think of $T S$ as the part of the system's energy that is disordered already, then $(H-T S)$ is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered
Also, $\Delta G=\Delta H-T \Delta S$
From the second law of thermodynamics, a reaction is spontaneous if $\Delta_{\text {total }} S$ is positive, non-spontaneous if $\Delta_{\text {total }} S$ is negative, and at equilibrium if $\Delta_{\text {total }} S$ is zero.
Since, $-T \Delta S=\Delta G$ and since $\Delta G$ and $\Delta S$ have opposite signs, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure
If $\Delta G< 0$, the reaction is spontaneous
If $\Delta G >0$, the reaction is non-spontaneous
If $\Delta G=0$, the reaction is at equilibrium
Read the above paragraph carefully and answer the following questions based on the above comprehension
For the spontaneity of a reaction, which statement is true?

Thermodynamics

Solution:

$\Delta H=-$ ve and $\Delta S=+$ ve, both favour the process