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Q. Four thin uniform rods each of length $L$ and mass $m$ are joined to form a square. The moment of inertia of square about an axis along its one diagonal is.

System of Particles and Rotational Motion

Solution:

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$I =4\left(\frac{m L^{2} \sin ^{2} 45^{\circ}}{3}\right)$
$=\frac{4 m L^{2}}{6}$
$=\frac{2}{3} m L^{2}$