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Q. Four spheres each having mass $m$ and radius $r$ are placed with their centres on the four corners of a square of side $a$ . Then the moment of inertia of the system about an axis along one of the sides of the square is :-
Question

NTA AbhyasNTA Abhyas 2020

Solution:

Solution
$I_{A B}=I_{1 A B}+I_{2 A B}+I_{3 A B}+I_{4 A B}$
$=\frac{2}{5}mr^{2}+\frac{2}{5}mr^{2}+\left(\frac{2}{5} m r^{2} + m a^{2}\right)+\left(\frac{2}{5} m r^{2} + m a^{2}\right)$
$=\frac{8}{5}mr^{2}+2ma^{2}$