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  4. Four resistance of 10 Ω, 60 Ω , 100 Ω and 200 Ω respectively taken in order are used to form a Wheatstone’s bridge. A 15 V battery is connected to the ends of a 200 Ω resistance, the current through it will be

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Q. Four resistance of $10\, \Omega, 60\, \Omega ,\, 100\, \Omega$ and $200\, \Omega$ respectively taken in order are used to form a Wheatstone’s bridge. A $15\,V$ battery is connected to the ends of a $200 \, \Omega$ resistance, the current through it will be

VITEEEVITEEE 2014Current Electricity

Solution:

Here, the resistance for $10\, \Omega,\, 60\, \Omega$ and $100\, \Omega$ are in series and they together are in parallel to $200\, \Omega$ resistance. When a potential difference of $15\, V$ is applied across $200\, \Omega$ then current through it is
$1=\frac{15}{200}=7.5 \times 10^{-2} A$