Question

Four plates of the same area of cross-section $A$ are joined as shown in the figure. The distance between each plate is d. The equivalent capacity across $A$ and $B$ will be

• A. $\frac{2 \varepsilon_{0} A}{d}$
• B. $\frac{3 \varepsilon_{0} A}{d}$
• C. $\frac{3 \varepsilon_{0} A}{2 d}$
• D. $\frac{\varepsilon_{0} A}{d}$

Answer 1

Answer: (B)

The given arrangement is equivalent to the parallel combination of three identical capacitors. Hence equivalent capacitance $=3 C=3 \frac{\varepsilon_{0} A}{d}$