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  4. Four plates of equal area A are separated by equal distances d and are arranged as shown in the figure. The equivalent capacity is

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Q. Four plates of equal area $A$ are separated by equal distances $d$ and are arranged as shown in the figure. The equivalent capacity isPhysics Question Image

Electrostatic Potential and Capacitance

Solution:

The given circuit is equivalent to a parallel combination two identical capacitors.
Hence, equivalent capacitance between $A$ and $B$ is
image
$C =\frac{\varepsilon_{0} A}{d}+\frac{\varepsilon_{0} A}{d}$
$=\frac{2 \varepsilon_{0} A}{d}$