1. Tardigrade
  2. Question
  3. Physics
  4. Four persons K , L , M , N are initially at the four corners of a square of side d . Each person now moves with a uniform speed v in such a way that K always moves directly towards L , L directly towards M , M directly towards N , and N directly towards K . The four persons will meet at a time

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Four persons $K$ , $L$ , $M$ , $N$ are initially at the four corners of a square of side $d$ . Each person now moves with a uniform speed $v$ in such a way that $K$ always moves directly towards $L$ , L directly towards $M$ , $M$ directly towards $N$ , and $N$ directly towards $K$ . The four persons will meet at a time

NTA AbhyasNTA Abhyas 2020Motion in a Plane

Solution:

The velocity of K throughout the motion towards the centre of the square is $v$ $ cos 45 ^\circ $ and the displacement covered by this velocity will be KO.
Solution
$\therefore \, t = \frac{ K O}{ v cos 45 ^\circ } = \frac{\left(\right. \sqrt{2} \frac{d}{2} \left.\right)}{\frac{v}{\sqrt{2}}} = \frac{d}{v}$