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  4. Four faces of a tetrahedral dice are marked with 2, 3, 4, 5. The lowest face is considered as a outcome.The number of ways in which a total of 33 can occur in 7 throws, is equal to

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Q. Four faces of a tetrahedral dice are marked with 2, 3, 4, 5. The lowest face is considered as a outcome.The number of ways in which a total of 33 can occur in 7 throws, is equal to

Permutations and Combinations

Solution:

$5555553 \Rightarrow \frac{7 !}{6 !}=7$
$5555544 \Rightarrow \frac{7 !}{5 ! 2 !}=21 $
$\therefore \text { Total ways }=28 $