Question

Formation of $PCl_3$ is explained on the basis of what hybridisation of phosphorus atom

• A. $SP^2$
• B. $SP^3$
• C. $SP^3 d$
• D. $SP^3 d^2$

Answer 1

Answer: (B)

The type of hybridisation in an atom can be determined By using the formula

$H=\frac{1}{2}[V+Y-C+A]$

Here, $V=$ valence shell electrons of the central atom

$Y=$ number of monovalent atom

$C=$ total positive charge and

$A=$ total negative charge In case of $PCl _{3}$

$H=\frac{1}{2}[5+3]=4$

Hybridisation of phosphorus atom is $s p^{3}$.



Pyramidal shape (due to presence of one lone pair of electron.)