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Q. Formation of ammonia is shown by the reaction,
$N_{2\left(g\right)}+3H_{2\left(g\right)} \to 2NH_{3\left(g\right)}$; $\Delta_{r}H^{\circ} = -91.8\,kJ\,mol^{-1}$
What will be the enthalpy of reaction for the decomposition of $NH_3$ according to the reaction?
$2NH_{3\left(g\right)}\to N_{2\left(g\right)} + 3H_{2\left(g\right)}; \Delta_{r}H^{\circ} = ?$

Thermodynamics

Solution:

The sign of $\Delta H$ is reversed.