Q. Forces 5N, 12N and 13N are in equilibrium If $ 1\text{ }km/h $ . then the angle between 5N force and 13N force is
BVP MedicalBVP Medical 2014
Solution:
As $ {{5}^{2}}+{{12}^{2}}={{13}^{2}} $ , so these forces will be acting along the side of a right angled triangle. Angle between 5N and 13N.
$ ={{180}^{o}}-({{90}^{o}}+{{23}^{o}}) $ $ ={{67}^{o}} $
