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Q. Force required to move a mass of $1 \,kg$ at rest on a horizontal rough plane ( $ \mu =0.1 $ and $ g=9.8\,m{{s}^{2}} $ ) is

WBJEEWBJEE 2008Laws of Motion

Solution:

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Given that $\mu=0.1$ and $g=9.8\, m / s ^{2}$
So, $F =f_{r}=\mu N=\mu mg$
$=0.1 \times 1 \times 9.8=0.98\, N$