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Q. Force $F$ on a particle moving in a straight line varies with distance $d$ as shown in figure. The work done on the particle during its displacement of $12\, m$ is
image

AIPMTAIPMT 2011Work, Energy and Power

Solution:

$wd =\int F \cdot dx$
which is area under $F-d$ curve
Area $= wd =2 \times 6+\frac{1}{2} \times 2 \times 6$
$=12+6 $
$=18\, J$