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  4. Force between two identical bar magnets whose centres are r metre apart is 4.8 N, when their axes are in the same line. If separation is increased to 2 r, the force between them is reduced to

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Q. Force between two identical bar magnets whose centres are $r$ metre apart is $4.8\, N$, when their axes are in the same line. If separation is increased to $2 r$, the force between them is reduced to

Magnetism and Matter

Solution:

In magnetic dipole, force $\propto \frac{1}{r^{4}}$
Hence, new force $=\frac{4.8}{2^{4}}=\frac{4.8}{16}=0.3\, N$