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Q. Force acts for $20 \,s$ on a body of mass $20\, kg$, starting from rest, after which the force ceases and then body describes $50\, m$ in the next $10 \,s$. The value of force will be :

JEE MainJEE Main 2023Laws of Motion

Solution:

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$ 50=V \times 10$
$V=5 \,m / s $
$ V =0+ a \times 20$
$ 5= a \times 20 $
$ a =\frac{1}{4} \,m / s ^2 $
$ F = ma =20 \times \frac{1}{4}=5 N $