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  4. Force acting on a test charge between the plates of a parallel capacitor is F. If one of the plates is removed, then the force on the same test charge will be :

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Q. Force acting on a test charge between the plates of a parallel capacitor is $F$. If one of the plates is removed, then the force on the same test charge will be :

Electrostatic Potential and Capacitance

Solution:

Electric field is between the plates and there is equal contribution from both the plates. When one plate is removed, the force is halved.