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Q. Force acting on a particle is $5\, N$. If the units of length and time are doubled and unit of mass is halved, then numerical value of the force in the new system will be

Physical World, Units and Measurements

Solution:

$n_{2}=n_{1}\left(\frac{M_{1}}{M_{2}}\right)^{^1}\left(\frac{L_{1}}{L_{2}}\right)^{^1}\left(\frac{T_{1}}{T_{2}}\right)^{^{-2}}$
$=5\left(\frac{M_{1}}{M_{1} / 2}\right)\left(\frac{L_{1}}{2L_{1}}\right)\left(\frac{T_{1}}{2T_{1}}\right)^{^{-2}}$
$=20$