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Q. For what value of $R$ , (in ohm) the current in galvanometer is zero?

Question

NTA AbhyasNTA Abhyas 2020Current Electricity

Solution:

Solution
$i=\frac{12}{R + 5}$
Potential difference across $R=2 \, V=\frac{12}{R + 5}\times \, R$
$\therefore \, 2=\frac{12}{R + 5}\times \, R$
$\Rightarrow \, R+5=6 \, R$
$\Rightarrow \, R=1 \, \Omega $