1. Tardigrade
  2. Question
  3. Chemistry
  4. For vaporization of water at 1 atmospheric pressure, the values of Δ H and Δ S are 40.63 kJ mol-1 and 108.8 JK-1 mol-1, respectively. The temperature when Gibbs energy change (Δ G) for this transformation will be zero, is

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Q. For vaporization of water at 1 atmospheric pressure, the values of $\Delta H$ and $\Delta S$ are $40.63 \, kJ \, mol^{-1}$ and $108.8 \, JK^{-1} mol^{-1}$, respectively. The temperature when Gibbs energy change $(\Delta G)$ for this transformation will be zero, is

AIPMTAIPMT 2010Thermodynamics

Solution:

$\Delta G = \Delta H - T \Delta S \Delta G =0 $
Given $ \Delta H = T \Delta S,$
$T = \frac{40.63 \times 10^{3}}{108.8 } = 373.4 K$