We have, $r=3 p+4 q\,\,\,...(i)$
and $2 r=p-3 q\,\,\,...(ii)$
On eliminating $p$, from Eqs. (i) and (ii), we get
$ r =3(2 r+3 q)+4 q$
$ r =6 r+9 q+4 q $
$\Rightarrow 5 r =-13 q $
$\Rightarrow r =-\frac{13}{5} q$
$\therefore r$ and $q$ have opposite directions.
Hence, $| r |>2| q |$