Question

For the strong electrolytes $NaOH, \, NaCl$ and $BaCl_{2}$ the molar ionic conductivities at infinite dilution are $250,125\text{and}300mho \, cm^{2}mol^{- 1}$ respectively. The molar conductivity of $Ba\left(O H\right)_{2}$ at infinite dilution ( $mho \, cm^{2}mol^{- 1}$ ) is.

Answer 1

$\lambda^{0}\left( Ba ( OH )_{2}\right)=\lambda^{0}\left( BaCl _{2}\right)+2 \lambda^{0}( NaOH )-2 \lambda^{0}( NaCl )$
$\lambda^{0}\left( Ba ( OH )_{2}\right)=300+2(250)-2(125)$
$\lambda^{0}\left( Ba ( OH )_{2}\right)=300+500-250$
$\lambda^{0}\left( Ba ( OH )_{2}\right)=550 mho cm ^{2} mol ^{-1}$