1. Tardigrade
  2. Question
  3. Chemistry
  4. For the reaction NO2 + CO → CO2+NO the experimental rate expression is -(dc/dt)=k[NO2]2 the number of molecules of CO involves in the slowest step will be

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Q. For the reaction $NO_2 + CO \to CO_2+NO$ the experimental rate expression is $-\frac{dc}{dt}=k\left[NO_{2}\right]^{2}$ the number of molecules of $CO$ involves in the slowest step will be

Chemical Kinetics

Solution:

Since there is no$\left[CO\right]$ involved in rate expression therefore $CO$ is involved in fast step.