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Q. For the reaction
$N_{2(s)}+O_{2(s)} \rightleftharpoons 2 N O_{(g)}$, the value of $K_{c}$ at $800^{\circ} C$ is $0.1 .$ When the equilibrium concentrations of both the reactants is $0.5 \,mol$, what is the value of $K_{P}$ at the same temperature?

KCETKCET 2005Equilibrium

Solution:

$N _{2}(g)+ O _{2}(g) \rightleftharpoons 2 NO (g)$

$K_{c}=0 . L_{p}=K_{c}(R T)^{\Delta n}$

$\Delta \,n=$ Number of gaseous product

- Number of gaseous reactants

$\Delta n=2-2=0 \quad \Delta n=0$

$\therefore K_{p}=K_{c}=0.1 $