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Q. For the reaction $N _{2}+3 H _{2} \rightleftharpoons 2 NH _{3}, N _{2}$ and $H _{2}$ were taken in the molar ratio of $1: 3$. Up to the point of equilibrium $50 \%$ each reactant has been reacted. If total pressure at equilibrium is $P$. The partial pressure of ammonia would be

Equilibrium

Solution:

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Total moles $=(1-0.5)+(3-1.5)+1=3 ; P_{ NH _{3}}=\frac{1}{3} P$