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Q. For the reaction,
$H _{2}(g)+ I _{2}(g) \rightleftharpoons 2 HI (g) ; K_{C}=57.0 \text { at } 700 K \text {. }$
The molar concentration of $\left[ H _{2}\right]=0.10 \,M$,
$\left[ I _{2}\right]=0.20 \,M$ and $[ HI ]=0.40\, M$.
The reaction quotient, $Q_{C}$ of the reaction is

Equilibrium

Solution:

Consider the gaseous reaction of $H _{2}$ with $I _{2}$.
$H _{2}(g)+ I _{2}(g) \rightleftharpoons 2 HI (g) ; K_{C}=57.0 \text { at } 700\, K$
$\Rightarrow Q_{C}=\frac{[ HI ]^{2}}{\left[ H _{2}\right]\left[ I _{2}\right]}=\frac{(0.40)^{2}}{(0.10) \times(0.20)}=8.0$