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Q. For the reaction equilibrium,
$N_{2} O_{4(g)} \rightleftharpoons 2NO_{2(g)}$ ; the concentration of $N_{2}O_{4}$ and $NO_{2}$ at equilibrium are $4.8 \times 10^{-2}$ and $1.2 \times 10^{-2}$ mol/L respectively. The value of Kc for the reaction is:

Equilibrium

Solution:

$K_c =\frac{\left[NO_{2}\right]^{2}}{\left[N_{2}O_{4}\right]}=\frac{\left(1.2\times10^{-2}\right)^{2}}{4.8\times10^{-2}}=3.0 \times10^{-3} M$