Question

For the reaction, $ C(s)+CO_{2}(g)2CO(g) $ the partial pressure of $ CO_{2} $ and $ CO $ are $2.0$ and $4.0$ arm respectively then equilibrium $ K_{p} $ for the reaction will be

• A. $ 0.5 $
• B. $ 8.0 $
• C. $ 4.0 $
• D. $ 32 $

Answer 1

Answer: (B)

For the reaction, $C(s)+ CO _{2}(g) 2 CO (g)$
$K_{p}=\frac{\text { partial pressure of gasseous products }}{\text { partial pressure of gasseous reactans }}$
$=\frac{P_{C O}^{2}}{P_{C O_{2}}}=\frac{4 \times 4}{2}=8$