Tardigrade
Question
Chemistry
For the reaction A+B arrow C ; starting with different initial concentration of A and B , initial rate of reaction were determined graphically in four experiments. 3.2× 10- 3 S.NO. [.A].0/M (Initial conc.) [.B].0/M (Initial conc.) rate/M sec-1 1 1.6× 10-3 5× 10-2 10-3 2 3.2× 10-3 5× 10-2 4× 10-3 3 1.6× 10-3 10-1 2× 10-3 4 3.2× 10- 3 10- 1 8× 10- 3 Rate law for reaction from above data is

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Q. For the reaction $A+B \rightarrow C$ ; starting with different initial concentration of $A$ and $B$ , initial rate of reaction were determined graphically in four experiments.
$3.2\times 10^{- 3}$

S.NO. $\left[\right.A\left]\right._{0}/M$ (Initial conc.) $\left[\right.B\left]\right._{0}/M$ (Initial conc.) $rate/M \,\sec^{-1}$

$1$ $1.6\times 10-3$ $5\times 10-2$ $10-3$

$2$ $3.2\times 10-3$ $5\times 10-2$ $4\times 10-3$

$3$ $1.6\times 10-3$ $10-1$ $2\times 10-3$

$4$ $3.2\times 10^{- 3}$ $10^{- 1}$ $8\times 10^{- 3}$

Rate law for reaction from above data is

NTA AbhyasNTA Abhyas 2022

Solution:

S.NO.	$\left[\right.A\left]\right._{0}/M$ (Initial conc.)	$\left[\right.B\left]\right._{0}/M$ (Initial conc.)	$rate/M \,\sec^{-1}$
$1$	$1.6\times 10-3$	$5\times 10-2$	$10-3$
$2$	$3.2\times 10-3$	$5\times 10-2$	$4\times 10-3$
$3$	$1.6\times 10-3$	$10-1$	$2\times 10-3$
$4$	$3.2\times 10^{- 3}$	$10^{- 1}$	$8\times 10^{- 3}$