Question

For the reaction
$5 Br ^{-}(a q)+6 H ^{+}(a q)+ BrO _{3}^{-}(a q) \longrightarrow 3 Br _{2}(a q)+3 H _{2} O (I) $
if, $-\frac{\Delta\left[ BrO _{3}^{-}\right]}{\Delta t}=0.01 \,mol\, L ^{-1} min ^{-1}$
$\frac{\Delta\left[ Br _{2}\right]}{\Delta t}$ in $mol \,L ^{-1}\, \min ^{-1}$ is

• A. 0.01
• B. 0.3
• C. 0.03
• D. 0.005

Answer 1

Answer: (C)

$5 Br ^{-}(a q)+6 H ^{+}(a q)+ BrO _{3}^{-}(a q) \longrightarrow 3 Br _{2}(a q)+3 H _{2} O (I)$

Since, we' ve $-\frac{1}{5} \frac{\Delta\left[ Br ^{-}\right]}{\Delta t }=-\frac{\Delta\left[ Bro _{3}^{-}\right]}{\Delta t }=+\frac{1}{3} \frac{\Delta\left[ Br _{2}\right]}{\Delta t }$

$\therefore \frac{\Delta BrO ^{-} 3}{\Delta t }=\frac{1}{3} \frac{\Delta\left[ Br _{2}\right]}{\Delta t }$

$\Rightarrow \frac{\Delta\left[ Br _{2}\right]}{\Delta t }=3 \frac{\Delta\left[ BrO _{3}^{-}\right]}{\Delta t }=3 \times 0.01=0.03$