Question

For the reaction, $4A+B \rightarrow 2C+2D$ , the statement not correct is

• A. The rate of disappearance of B is 1/4 the rate of disappearance of A
• B. The rate of appearance of C is half the rate of disappearance of B
• C. The rate of formation of D is half the rate of consumption of A
• D. The rates of formation of C and D are equal

Answer 1

Answer: (B)

Here statement in option B is incorrect while rest other statements are correct as
$-\frac{1}{4}\frac{d A}{d t}=\frac{- d B}{d t}=\frac{1}{2}\frac{d C}{d t}=\frac{1}{2}\frac{d D}{d t}$
$-\frac{1}{4}\frac{d A}{d t}==\frac{1}{2}\frac{d C}{d t}$
$\frac{d C}{d t}=\frac{1}{2}\frac{d A}{d t}=\frac{2 d B}{d t}$
Hence the rate of appearance of C is twice the rate of disappearance of B.