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Q. For the reaction, $4 NH_{3}(g) + 5O_{2}(g) \rightleftharpoons 4 NO(g) + 6 H_{2}O(l), \Delta H =$ positive.
At equilibrium the factor that will not affect the concentration of $NH_{3}$ is:

Equilibrium

Solution:

Catalyst can’t disturb the state of the equilibrium.