Question

For the reaction, $4 KClO _{3} \rightarrow 3 KClO _{4}+ KCl$ if $\frac{-d\left[ KClO _{3}\right]}{dt}=k_{1}\left[ KClO _{3}\right]^{4}, \frac{d\left[ KClO _{4}\right]}{dt}=k_{2}\left[ KClO _{3}\right]^{4}$, $\frac{d[ KCl ]}{d t}=k_{3}\left[ KClO _{3}\right]^{4}$ ,
the correct relation between $k_{1}, k_{2}$ and $k_{3}$ is

• A. $k_{1}=k_{2}=k_{3}$
• B. $4 k_{1}=3 k_{2}=k_{1}$
• C. $3 k_{1}=4 k_{2}=12 k_{3}$
• D. none of these

Answer 1

Answer: (C)

Rate $=-\frac{1}{4} \frac{d\left[ KClO _{3}\right]}{d t}=\frac{1}{3} \frac{d\left[ KClO _{4}\right]}{d t}=\frac{d[ KCl ]}{d t}$

or $ \frac{k_{1}}{4}\left[ KClO _{3}\right]^{4}=\frac{k_{2}}{3}\left[ KClO _{3}\right]^{4}=k_{3}\left[ KClO _{3}\right]^{4}$

or $3 k_{1}=4 k_{2}=12 k_{3}$