Question

For the process $H_2O(l)(1$bar, $373 \,K) \to H_2O_{(g)} (1$ bar, $373 \,K)$, the correct set of thermodynamic parameters is

• A. $\Delta G =0, \,\Delta S = +ve$
• B. $\Delta G =0, \,\Delta S = -ve$
• C. $\Delta G =+ve\,\Delta S = 0$
• D. $\Delta G =-ve\,\Delta S = +ve$

Answer 1

Answer: (A)

Since, liquid is passing into gaseous phase so entropy will increase and at $373 \,K$ during the phase transformation it remains at equilibrium. So, $\Delta G = 0$