1. Tardigrade
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  4. For the medium with relative permittivity ϵr = 4 and relative permeability μr = 6.25, the velocity of light is given as (c is velocity of light in vacuum)

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Q. For the medium with relative permittivity $\epsilon_r$ = 4 and relative permeability $\mu_r$ = 6.25, the velocity of light is given as (c is velocity of light in vacuum)

Solution:

$v = \frac{1}{\sqrt{\mu_{o}\varepsilon_{o} \mu_{r}\varepsilon_{r}}}= \frac{c}{\sqrt{\varepsilon_{r}\mu_{r}}}$
$= \frac{c}{\sqrt{4\times6.25}}= \frac{c}{\sqrt{25}}=\frac{c}{5}$