Q.
For the given situation as shown in the figure, the value of $\theta$ to keep the system in equilibrium will be
Solution:
In eqbm,
$T_{1} \cos \theta=T_{2}=60 N . \ldots(1)$
$T_{1} \sin \theta=60 N \ldots(2)$
$\therefore \quad \tan \theta=1 \Rightarrow \theta=45^{\circ}$
