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Chemistry
For the given rate expression =k[A]3 / 2[B]-1, the overall order of a reaction is
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Q. For the given rate expression $=k[A]^{3 / 2}[B]^{-1}$, the overall order of a reaction is
Chemical Kinetics
A
zero
9%
B
half
70%
C
one
15%
D
two
6%
Solution:
Rate $=k[A]^{x}[B]^{y}$
order $=x +y$
$\therefore$ Order is $\left(\frac{3}{2}\right)+(-1)=1 / 2$, i.e. half-order.