Question

For the four sets of three measured physical quantities as given below. Which of the following options is correct ?
$(i)\, A_1 = 24.36, B_1 = 0.0724, C_1 = 256.2$
$(ii) \,A_2 =24.44, B_2 = 16.082, C_2 = 240.2$
$(iii) \,A_3 = 25.2, B_3 = 19.2812, C_3 = 236.183$
$(iv)\, A_4 = 25, B_4 = 236.191, C_4 = 19.5$

• A. $A_{4}+B_{4}+C_{4} < A_{1}+B_{1}+C_{1}=A_{2}+B_{2}+C_{2}=A_{3}+B_{3}+C_{3}$
• B. $ A_{1}+B_{1}+C_{1}=A_{2}+B_{2}+C_{2}=A_{3}+B_{3}+C_{3}=A_{4}+B_{4}+C_{4}$
• C. $A _{1}+ B _{1}+ C _{1}< A _{3}+ B _{3}+ C _{3}< A _{4}+ B _{4}+ C _{4}< A _{2}+ B _{2}+ C _{2}$
• D. $A_{4}+B_{4}+C_{4} < A_{1}+B_{1}+C_{1} < A_{3}+B_{3}+C_{3} < A_{2}+B_{2}+C_{2}$

Answer 1

Answer: (C)

$A _{1}+ B _{1}+ C _{1}=24.36+0.0724+256.2=280.6324$
$A _{2}+ B _{2}+ C _{2}=24.44+16.082+240.2=280.722$
$A _{3}+ B _{3}+ C _{3}=25.2+19.2812+236.183=280.6642$
$A _{4}+ B _{4}+ C _{4}=25+236.191+19.5=280.691$
$\left( A _{2}+ B _{2}+ C _{2}\right)>\left( A _{4}+ B _{4}+ C _{4}\right)>\left( A _{3}+ B _{3}+ C _{3}\right) \cdot\left( A _{1}+ B _{1}+ C _{1}\right)$