Question

For the formation of $3.65\, g$ of HCl gas, what volume of hydrogen gas and chlorine gas are required at NTP conditions?

• A. 1 L , 1 L
• B. 1.12 L , 2.24 L
• C. 3.65 L , 1.83 L
• D. 1.12 L , 1.12 L

Answer 1

Answer: (D)

For $(36.5 \times 2) g$ of $HCl$ volume of $H _{2}$ and $Cl _{2}$ required will be $22.4\, L\, H _{2}$ and $22.4\, L$ of $CL _{2}$
$\therefore $ For $3.65\, g$ and $1.12\, L$ of $H _{2}$
$1.12\, L$ of $\left.Cl _{2}\right\}$