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Q. For the following three reactions 1, 2 and 3, equilibrium constants are given:
$(1) CO_{(g)} +H_{2}O_{(g)} \rightleftharpoons CO_{2(g)} +H_{2(g)};K_{1}$
$(2) CH_{4(g)} +H_{2}O_{(g)} \rightleftharpoons CO_{(g)} +3H_{2(g)};K_{2}$
$(3) CH_{4(g)} +2H_{2}O_{(g)} \rightleftharpoons CO_{2(g)} +4H_{2(g)};K_{3}$
Which of the following relations is correct?

Equilibrium

Solution:

$CO(g) + H_{2}O (g) \rightleftharpoons CO_{2} (g) +H_{2} (g) ;K_{1} . . . . (i)$
$CH_{4}(g) + H_{2}O (g) \rightleftharpoons CO(g) +3H_{2} (g) ;K_{2}. . . . . (ii)$
$CH_{4}(g) + 2H_{2}O (g) \rightleftharpoons CO_{2} (g) +4H_{2} (g) ;K_{3}. . . . . . (iii)$
$Eq. (iii) = eq. (i) + eq. (ii)$
Thus, $K_{3} = K_{1} . K_{2}$