1. Tardigrade
  2. Question
  3. Chemistry
  4. For the following reaction, the equilibrium constant Kc at 298 K is 1.6 x 1017. Fe2+ (aq) + S2- (aq) <=> FeS (s) When equal volumes of 0.06 M Fe2+(aq) and 0.2 M S2- (aq) solutions are mixed, the equilibrium concentration of Fe2+ (aq) is found to be Y × 1017 M. The value of Y is

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Q. For the following reaction, the equilibrium constant $K_c$ at $298\, K$ is $1.6 x 10^{17}$.
$\ce{Fe^2+ (aq) + S^2- (aq) <=> FeS (s)}$
When equal volumes of $0.06$ M $Fe^{2+}(aq)$ and $0.2$ M $S^{2-} (aq)$ solutions are mixed, the equilibrium concentration of $Fe^{2+}$ (aq) is found to be $Y \times 10^{17}$ M. The value of $Y$ is______

JEE AdvancedJEE Advanced 2019

Solution:

$Fe^{2+}\left(aq\right)+S^{2-}\left(aq\right) {\rightleftharpoons} FeS\left(s\right),\quad\quad K = 1.6\times10^{17}$
$t_{0} \quad0.03\quad0.1\quad-$
$t_{aq}\quad\times\quad0.1-0.03\quad-$
$\simeq 0.07$
$\therefore \,x\left(0.7\right) = \frac{1}{1.6}\times10^{-17}$
$\Rightarrow \,x = 8.93 \times 10^{-17} \,M$
$\therefore \,Y = 8.93$